In the figure shown,frac{sin i}{sin r} is equ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Snell's Law at the first interface between medium $\mu_1$ and $\mu_2$:$\mu_1 \sin i = \mu_2 \sin r_1$where $r_1$ is the angle of refr

Vedclass · Accepted Answer

$\frac{\mu_3}{\mu_1}$

Vedclass · Answer

(B) According to Snell's Law at the first interface between medium $\mu_1$ and $\mu_2$:$\mu_1 \sin i = \mu_2 \sin r_1$where $r_1$ is the angle of refraction in the second medium.At the second interface between medium $\mu_2$ and $\mu_3$:$\mu_2 \sin r_1 = \mu_3 \sin r$where $r$ is the angle of refraction in the third medium.From these two equations,we can equate the common term $\mu_2 \sin r_1$:$\mu_1 \sin i = \mu_3 \sin r$Therefore,the ratio is:$\frac{\sin i}{\sin r} = \frac{\mu_3}{\mu_1}$

In the figure shown,$\frac{\sin i}{\sin r}$ is equal to:

Similar Questions

When light is incident on a medium at an angle $i$ and refracted into a second medium at an angle $r$,the graph of $\sin i$ vs $\sin r$ is as shown. From this,one can conclude that:

If the speed of light in vacuum is $C \ m/s$,then what is the velocity of light in a medium of refractive index $1.5$?

$A$ light beam is travelling from Region $I$ to Region $IV$ (Refer Figure). The refractive indices in Regions $I$,$II$,$III$,and $IV$ are $n_0$,$\frac{n_0}{2}$,$\frac{n_0}{6}$,and $\frac{n_0}{8}$,respectively. The angle of incidence $\theta$ for which the beam just misses entering Region $IV$ is:

The refractive index of air is $1.0003$. The thickness of an air column that will contain one more wavelength of yellow light $(6000 \mathring A)$ than in the same thickness in a vacuum is:

The refractive index of a medium is $\mu$ and the wavelength of light in that medium is $\lambda$. Which of the following proportionality relations is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module